Webdetermine whether f (x)=4x^ (2)-16x+6 has a maximum or minimum value and find that value. We have an Answer from Expert. WebTo find critical points of a function, take the derivative, set it equal to zero and solve for x, then substitute the value back into the original function to get y. Check the second …
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WebMar 21, 2014 · You can see whether x=2 is a local maximum or minimum by using either the First Derivative Test (testing whether f'(x) changes sign at x=2) or the Second Derivative Test (determining … WebTherefore function has minima at x = 5, So, now the minimum value of the function will be f ( x) m i n = 5 2 + 250 5 = 25 + 50 = 75 Therefore the minimum value of the function is 75. Hence option A, 75 is the correct answer. Suggest Corrections 0 Similar questions Q. The minimum value of 2 x2+x−1 is Q. Find the minimum value of (5+x)(2+x)(1+x). Q. entwistle green burnley property for sale
Find the absolute maximum and minimum values of $f(x,y) = y^{2}+x^{2 …
WebMay 4, 2024 · The minimum value of f (x) = x4 – x2 – 2x + 6 is : A. 6 B. 4 C. 8 D. none of these maxima and minima class-12 1 Answer +1 vote answered May 4, 2024 by Zafaa … Web4. (Exercise 22) Find the minimum/maximum of f(x;y) = 2x2 +3y2 4x 5 when x2 +y2 16. We can look for extrema separately when x2 + y2 < 16 and x2 + y2 = 16. For the former, we have fx(x;y) = 4x 4 and fy(x;y) = 6y, so the only critical point is (1;0) with value f(1;0) = 7.For the latter we use Lagrange multipliers with the constraint x2 +y2 = 16. We get the equations WebQuestion: (1 point) Find the global maximum and global minimum values of the function f (x) = x - 6x² - 63x + 4 over each of the indicated intervals. (a) Interval = (-4,0]. 1. Global … dr holly salem